Subjective synonymy
When DA(A, C) ¨ p/2 
& DA(B, C) ¨ p/2
then SynS(A, B,
C) ¨ DA(A,B)
& DA(B, C) ¨ p/2 then SynS(A, B,
C) ¨ DA(A,B)SynS(A, B, 0) = DA(A,
B)
SynS(A, A, C) = 0
SynS(A, B, B) = DA(A-A€B, 0) = p/2
¥DA(tit, crow)
= 0.32
= 0.32 ¥SynS(tit, crow, zoology) =
0.54
=
0.54¥SynS(tit, crow, bird) =
1.07
=
1.07¥SynS(tit, crow, passerine) =
1.37
=
1.37